Skip to content Skip to sidebar Skip to footer

How To Open A Particular Directory Using Uri?

I want to open a particular directory (in a file explorer app) where images saved by my app are stored. I can get the Uri of that directory by Uri.parse(imagesDir.getAbsolutePath()

Solution 1:

I want to open a particular directory where images saved by my app are stored

Android has never really supported this.

I can get the Uri of that directory by Uri.parse(imagesDir.getAbsolutePath()).

That is an invalid Uri. At best, use Uri.fromFile(imagesDir).

This is how my code looks as of now

ACTION_OPEN_DOCUMENTdoes not take a Uri in the "data" facet.

The closest thing to what you want is to add EXTRA_INITIAL_URI to the Intent. However, this is only documented to work with a Uri that you previously obtained from ACTION_OPEN_DOCUMENT or ACTION_OPEN_DOCUMENT_TREE. It is unlikely to work with a Uri from some place else, such as from some File.

Solution 2:

SAF is pain. Uri.fromFile(file.getAbsolutePath()) doesn't work because returns uri likes file://sdcard.... But DocumentsContract.EXTRA_INITIAL_URI works with content. Below works for me:

privatevoidselectDir() {
    Urid= Uri.parse("content://com.android.externalstorage.documents/document/primary:Download");
    Intentintent=newIntent(Intent.ACTION_OPEN_DOCUMENT);
    intent.addCategory(Intent.CATEGORY_OPENABLE);
    intent.setType("*/*");
    intent.putExtra(DocumentsContract.EXTRA_INITIAL_URI, d);
    startActivityForResult(intent, PICK_WDI_FILE);
}

Post a Comment for "How To Open A Particular Directory Using Uri?"