Get Localized Short Date Pattern As String?

I'd like to get the pattern of a 'short date' as a String that is customized to the user's locale (e.g. 'E dd MMM'). I can easily get a localized DateFormat-object using DateFormat

Solution 1:

I ended up using

String deviceDateFormat = DateFormat.getBestDateTimePattern(Locale.getDefault(), "E dd MMM");

will will give me the "best regional representation" of the supplied input-format, in this case the weekday, day, and month.

Solution 2:

remember DateFormat is the base class for SimpleDateFormat so you can always cast it and grab the pattern.

finalDateFormatshortDateFormat= android.text.format.DateFormat.getDateFormat(context.getApplicationContext());

// getDateFormat() returns a SimpleDateFormat from which we can extract the patternif (shortDateFormat instanceof SimpleDateFormat) {
    finalStringpattern= ((SimpleDateFormat) shortDateFormat).toPattern();

Solution 3:

You could try with something like this :

public String toLocalHourOrShortDate(String dateString, Context context) {
    java.text.DateFormat dateFormat = DateFormat.getDateFormat(context);
    SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.getDefault());
    Date date = null;
    try {
        date = sdf.parse(dateString);
        Calendar thisMoment = Calendar.getInstance();
        Calendar eventTime = new GregorianCalendar(Locale.getDefault());
        eventTime.setTime(date);
        if (thisMoment.get(Calendar.YEAR) == eventTime.get(Calendar.YEAR) &&
                thisMoment.get(Calendar.MONTH) == eventTime.get(Calendar.MONTH) &&
                thisMoment.get(Calendar.DAY_OF_MONTH) == eventTime.get(Calendar.DAY_OF_MONTH)) {
            SimpleDateFormat hourDateFormat = new SimpleDateFormat("HH:mm", Locale.getDefault());
            return hourDateFormat.format(eventTime.getTime());
        }
    } catch (ParseException e) {
        e.printStackTrace();
    }
    return dateFormat.format(date);
}

Does that work for you ?